July 29th, 2009
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July 29th, 2009 at 10:15 am
When I was in pre-calculus, there was a 10-Day Pre-Cal syllabus. One of the days was, “Show them the video of the student factoring x^2 + y^2 = (x+y)^2 and getting HIT BY A TRAIN” so that made me laugh a lot!
July 29th, 2009 at 10:29 am
Alas! Would that the world were a commutative ring of characteristic 2…
July 29th, 2009 at 10:50 am
But my computer says:
sage: R. = GF(2)[]
sage: (x+y)^2
x^2 + y^2
;)
July 29th, 2009 at 2:25 pm
Okay, this comic goes on my office door. (Of course, that is why Z_2 is so nice.)
July 29th, 2009 at 2:26 pm
Oh, I just saw Jim Vaught’s comment. He already got the commutative ring of characteristic 2. Foiled again.
July 29th, 2009 at 7:28 pm
mod 2 and it works fine
July 29th, 2009 at 9:34 pm
We call this the freshman dream.
July 30th, 2009 at 3:08 am
I only came here to suggest trying it in Z_2, but since you beat me to it, I could point out that it also works in Z_1 …
July 30th, 2009 at 3:52 am
Another one: anticommutative rings!
July 30th, 2009 at 5:36 am
It works for boolean algebra too, though admittedly I’ve never seen exponents used to represent iterated AND gates. That would be a seriously cute notational convention.
July 30th, 2009 at 11:07 am
I’m a math tutor at a college campus…I’m definitely going to hang this up in the room. Printed out very large.
August 6th, 2009 at 2:47 pm
Doesn’t every equation work in Z_1?
August 27th, 2009 at 3:26 pm
well
this is funny….but also stupid mistake
June 11th, 2010 at 9:09 pm
It works in any Z_p. (x+y)^p == x^p+y^p (p)